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25x^2+30x+4=-4
We move all terms to the left:
25x^2+30x+4-(-4)=0
We add all the numbers together, and all the variables
25x^2+30x+8=0
a = 25; b = 30; c = +8;
Δ = b2-4ac
Δ = 302-4·25·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10}{2*25}=\frac{-40}{50} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10}{2*25}=\frac{-20}{50} =-2/5 $
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